*Solution :*

*Solution :*

**B = 14m, H =12m****As we know that :****Pressure = (depth x density)****Thrust = (pressure x area)**

**An right angle triangle PBC , PB =7m****Since, Height divide AB equally into two parts.****Triangle PBC and FEC are similar****So by law of similar angle triangle**

**PB/ FE = PC / FC****7 / FE =12 / 9**

**Hence, FE = (63 / 12)**** = 5.25m**

**In triangle DEC****DF = FE****DE = (2 X FE)**** = 2X 5.25**** =10.5m**

**Area of triangle DEC = (1/2 x10.5×9)**** =47.25m ^{2}**

**Pressure = (depth x density)**** = (9 x 1/3 x 1.025)**** = 3.075 t/m ^{2}**

**Hence Thrust experienced = (P X A)**** = (3.075 x 47.25)**** =145. 29 t**