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Solution:
Radius = (d/2)
=(1.2m/2)
= 0.6m
H = 2m, D =1.4m , RD = 1.016
Mass of the cylinder = (r2 h) x(density)
= (3.1416 x 0.6 x 0.6 x 2) x (1.016)
= 2.298t
Mass of the cylinder at 1.4m = 1.4 x r2 h) x (density)
= 1.4 x (3.1416 x 0.6 x0 .6) x (1.016)
= 1.608 t
Hence ,the maximum mass of lead shots that can be put in it with sinking is (2.298 t – 1.608 t) = 0.69 t