A cylindrical tank of diameter 8m is 10m high.400t of oil of RD 0.9 is poured into it. Find the ullage, assuming π to be 3.1416.

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Given: Diameter = 8m and height = 10m

qes 2

Radius = (d/2)m
=(8/2)m
=4m
Height =10m
Mass = 400t
RD =0.9

We know that:
Volume of the cylindrical tank = π2h
= 3.1416 x 4 x 4 x 10
=502.656m3

We also know that:
Density = (Mass/Volume)
0.9 = 400/ (Volume of the oil)

Hence, Volume of the oil = 400/0.9
=444.44m3

Depth of oil = volume/area
Area of cylinder   =( π2r)
 =(3.1416 x 4 x 4)
 =502656m3

We can calculate Depth of oil = (volume of oil)/ ( area of cylinder)
 = (444. 44)/(50.2656 )
=8.8418 m

Hence, ullage  = (10 – 8.8418)  =1.1582m

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