A rectangular lock gate 40m wide and 20m high has water of RD 1.010 12m deep on one side and water of RD 1.020 11m deep on the other. Find the resultant thrust experienced and direction in which it acts.

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Solution: 

Water of RD =1.010
                Depth =12 m
                C = (12/2)
                  =6m

Pressure = (depth x density)
                  =(6 x1.010) t/m2

Thrust =(P x A)  =( 6 x 1.010 x40 x12)
                          = 2908.8t

Water of RD = 1.020
Depth = 11m
C = (11/2)
   =5.5m

Pressure =(depth x density)
              = (5.5 x 1.020 ) t/m2

Area =( L X B) =(40 x 11)
                      = 440m2

Thrust =( P X A) = (5.5 x 1.020 x 440)
                           = 2468.4 t

Thus we can Resultant thrust =(2908.8 – 2468.4)
                                                      = 440.4t

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