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Given :
Depth of the tank is = 10.5m
Volume of the tank = 8200m3
Depth of the trunkway = 0.5m
Volume of the trunkway = 200m3
RD of the oil = 0.8
According to question, 2% of the tank volume left for expansion .
Volume of the tank alone = (8200-200)
= 8000m3
Height of the tank alone = (10.5 -0.5)
= 10 m
2% of the volume of the tank left for expansion .
= (2/100 x 8200)
=164m3
Volume of the oil to be load = (8200 -164)
=8036 m3
Mass of oil to be load = ( volume x density)
= (8036 x 0.8)
= 6428.8t
Volume of the trunkway = (L x B x 0.5)
= 200m3 ( given)
We can calculate Area as = (200 /0.5)
=400m2