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*Given :*

*Given :*

**Depth of the tank is = 10.5m****Volume of the tank = 8200m ^{3}**

**Depth of the trunkway = 0.5m**

**Volume of the trunkway = 200m**^{3}

**RD of the oil = 0.8****According to question, 2% of the tank volume left for expansion .****Volume of the tank alone = (8200-200)****= 8000m ^{3}**

**Height of the tank alone = (10.5 -0.5)****= 10 m**

**2% of the volume of the tank left for expansion .****= (2/100 x 8200)****=164m ^{3}**

**Volume of the oil to be load = (8200 -164)****=8036 m ^{3}**

**Mass of oil to be load = ( volume x density)****= (8036 x 0.8)****= 6428.8t**

**Volume of the trunkway = (L x B x 0.5)****= 200m ^{3} ( given)**

**We can calculate Area as = (200 /0.5)****=400m ^{2}**

**Volume of the free space = ullage= (volume of the free space)/(area)**

** = (164/ 400)m**

** =0.41m.**

**Volume of the free space = ullage= (volume of the free space)/(area)**

**= (164/ 400)m**

**=0.41m.**