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Given :
The total depth of tank =21m
Volume of the tank = 20600m3
The height of the trunkway = 1m
Volume of the trunkway = 600m3
Oil loaded = 16320t
RD= 0.8
The height of the tank = (21-1)
= 20m
Volume of the tank= (20600 – 600)
=20000m3
Area of tank = (20000 /20)
=10000m2
Volume of the oil = (mass /density)
=(1620 /0.8)
= 20400 m3
Hence, Volume of the oil inside the trunkway = (Total volume of the oil – volume of the tank)
= (20400 – 20000)
=400m3
Depth of the oil = (volume /area)
= (400/600)
= 0.66m