A vessel displaces 14500 tonnes, if floating in SW up to her winter load- line. If she is in a dock of RD 1.010 , with her winter load- line on the surface water, find how much cargo she can load, so that she would float at her winter load-line in SW.

Solution:

Displacement (W )= 14500t
RD = 1.025

Displacement (W) =( u/w volume ) x (density)
= (L x B x draft)  x  (1.025)

Draft = W /( L x B x 1.025)

Let W1 be the displacement at RD of 1.010

So W1 = (u/w volume )x( density)
= (L x B x d1 ) x  (1.010)
Hence, d1 = W1 / (L x B x 1.010)

According to question, Draft  = d1

So, W / ( L x B x 1.025)  =  W1 / (L x B x 1.010)
14500 / (L x B x 1.025) =  W1 / (L x B x 1.010)
W1   = (14500 x 1.010) / 1.025
= 14287.8 t

Hence, Cargo to load = (14500 – 14287.8)
= 212.2t.